JEE Mains · Physics · STD 12 - Nuclei
- JEE Mains 2021
- Hard
- Numerical
Calculate the time (in \(minutes\)) interval between \(33 \,\%\) decay and \(67\, \%\) decay if half-life of a substance is \(20\, minutes.\)
Pick an option to check your answer.
Answer & Solution
Correct Answer
(B) \(20\)
Step-by-step Solution
Detailed explanation
\(N _{1}= N _{0} e ^{-\lambda t_{1}}\)
\(\frac{ N _{1}}{ N _{0}}= e ^{-\lambda t _{1}}\)
\(0.67= e ^{-\lambda t _{1}}\)
\(\ln (0.67)=-\lambda t _{1}\)
\(N _{2}= N _{0} e ^{-\lambda t _{2}}\)
\(\frac{ N _{2}}{ N _{0}}= e ^{-\lambda t _{2}}\)
\(0.33= e ^{-\lambda t _{2}}\)
\(\ln (0.33)=-\lambda t _{2}\)
\(\ln (0.67)-\ln (0.33)=\lambda t _{1}-\lambda t _{2}\)
\(\lambda\left( t _{1}- t _{2}\right)=\ln \left(\frac{0.67}{0.33}\right)\)
\(\lambda\left( t _{1}- t _{2}\right) \cong \ln 2\)
\(t _{1}- t _{2} \simeq \frac{\ln 2}{\lambda}= t _{1 / 2}\)
Half life \(= t _{1 / 2}=20\,minutes.\)
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