JEE Mains · Physics · STD 12 - 12. atoms
The ratio of the magnitude of the kinetic energy to the potential energy of an electron in the \(5^{\text {th }}\) excited state of a hydrogen atom is _______.
- A \(4\)
- B \(\frac{1}{4}\)
- C \(\frac{1}{2}\)
- D \(1\)
Answer & Solution
Correct Answer
(C) \(\frac{1}{2}\)
Step-by-step Solution
Detailed explanation
\(\frac{1}{2}|P E|=K E\) for each value of \(\mathrm{n}\) (orbit) \(\therefore \frac{K E}{|P E|}=\frac{1}{2}\)
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