When a current of \(5\ mA\) is passed through a galvanometer having a coil of resistance \(15\ \Omega\), it shows full scale deflection. The value of the resistance to be put in series with the galvanometer to convert it into to voltmeter of range \(0 - 10\ V\) is

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Answer & Solution

Correct Answer

(A) \(1.985 \times 10^3\) \(Ω\)

Step-by-step Solution

Detailed explanation

Given : Current through the galvanometer, \(i_{g}=5 \times 10^{-3} \,A\)

Galvanometer resistance, \(G=15\, \Omega\)

Let resistance \(R\) to be put in series with the galvanometer to convert it into a voltmeter.

\(V=i_{g}(R+G)\)

\(10= 5 \times 10^{-3}(R+15) \)

\( \therefore \quad R=2000-15=1985 \)

\(=1.985 \times 10^{3} \,\Omega \)

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