JEE Mains · Maths · STD 12 - 8. Application and integration
Let \(A_{1}=\left\{(x, y):|x| \leq y^{2},|x|+2 y \leq 8\right\}\) and \(A_{2}=\{(x, y):|x|+|y| \leq k\}\). If \(27\) (Area \(\left.A _{1}\right)=5\) (Area \(A _{2}\) ), then \(k\) is equal to
- A \(6\)
- B \(8\)
- C \(10\)
- D \(12\)
Answer & Solution
Correct Answer
(A) \(6\)
Step-by-step Solution
Detailed explanation
\(A_{1}=\left\{(x, y):|x| \leq y^{2},|x|+2 y \leq 8\right\}\) and \(A_{2}=\{(x, y):|x|+|y| \leq k\} \text {. }\) area \(\left(A_{1}\right)=2\left[\int\limits_{0}^{2} y^{2} d y+\int\limits_{2}^{4}(8-2 y) d y\right]\)…
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