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JEE Mains · Physics · STD 12 - Atoms
  • JEE Mains 2026
  • Hard
  • MCQ

Two electrons are moving in orbits of two hydrogen like atoms with speeds \(3 \times 10^5 m / s\) and \(2.5 \times 10^5 m / s\) respectively. If the radii of these orbits are nearly same then the possible order of energy states are _________ respectively.

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Answer & Solution

Correct Answer

(A) 6 and 5

Step-by-step Solution

Detailed explanation

\( V\propto\frac{Z}{n} \)
\( r\propto\frac{n^{2}}{Z} \)
Thus; \( r\propto\frac{n}{v} \)
Radii are same then
\( \frac{n_{1}}{V_{1}}=\frac{n_{2}}{V_{2}} \)
\( \frac{n_{1}}{n_{2}}=\frac{3\times10^{5}}{2.5\times10^{5}}=\frac{6}{5} \)
Possible order is 6 and 5
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