JEE Mains · Physics · STD 12 - 12. atoms
Two electrons are moving in orbits of two hydrogen like atoms with speeds \(3 \times 10^5 m / s\) and \(2.5 \times 10^5 m / s\) respectively. If the radii of these orbits are nearly same then the possible order of energy states are _________ respectively.
- A 6 and 5
- B 9 and 8
- C 8 and 10
- D 10 and 12
Answer & Solution
Correct Answer
(A) 6 and 5
Step-by-step Solution
Detailed explanation
\( V\propto\frac{Z}{n} \) \( r\propto\frac{n^{2}}{Z} \) Thus; \( r\propto\frac{n}{v} \) Radii are same then \( \frac{n_{1}}{V_{1}}=\frac{n_{2}}{V_{2}} \) \( \frac{n_{1}}{n_{2}}=\frac{3\times10^{5}}{2.5\times10^{5}}=\frac{6}{5} \) Possible order is 6 and 5
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