JEE Mains · Physics · STD 12 - 14. Semicondutor electronics
From the given transfer characteristic of a transistor in \(CE\) configuration, the value of power gain of this configuration is \(10^{ x }\), for \(R_B=10\,k \Omega\), and \(R _C=1\,k \Omega\). The value of \(x\) is \(.....\).
- A \(6\)
- B \(9\)
- C \(3\)
- D \(12\)
Answer & Solution
Correct Answer
(C) \(3\)
Step-by-step Solution
Detailed explanation
Power gain \(\Rightarrow A _{ V } \cdot A _1= B \frac{ R _{ C }}{ R _{ B }} \cdot B = B ^2 \frac{ R _{ C }}{ R _{ B }}\) \(=\left(\frac{(20-10) \times 10^{-3}}{(200-100) \times 10^{-6}}\right) \times \frac{1 \times 10^3}{10 \times 10^3}=10^3\) Hence \(x =3\)
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