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JEE Mains · Physics · STD 12 - Nuclei
  • JEE Mains 2021
  • Medium
  • Numerical

The nuclear activity of a radioactive element becomes \(\left(\frac{1}{8}\right)^{\text {th }}\) of its initial value in \(30\, years.\) The half-life of radioactive element is \(....\,years.\)

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Answer & Solution

Correct Answer

(B) \(10\)

Step-by-step Solution

Detailed explanation

\(A = A _{0} e ^{-\lambda t }\)

\(\frac{ A _{0}}{8}= A _{0} e ^{-\lambda t } \Rightarrow \lambda t =\ln 8\)

\(\lambda t =3 \ln 2\)

\(\frac{\ln 2}{\lambda}=\frac{ t }{3}=\frac{30}{3}\)

\(10\;years\)

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