ExamBro
ExamBro
JEE Mains · Physics · STD 11 - 5. work,energy,power and collision

Four particles \(A, B, C, D\) of mass \(\frac{\mathrm{m}}{2}, \mathrm{~m}, 2 \mathrm{~m}, 4 \mathrm{~m}\), have same momentum, respectively. The particle with maximum kinetic energy is _______.

  1. A \(\mathrm{D}\)
  2. B \(\mathrm{C}\)
  3. C \(\mathrm{A}\)
  4. D  \(B\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(\mathrm{A}\)

Step-by-step Solution

Detailed explanation

\(\mathrm{KE}=\frac{\mathrm{p}^2}{2 \mathrm{~m}}\) Same momentum, so less mass means more \(\mathrm{KE}\). So \(\frac{\mathrm{m}}{2}\) will have \(\max\). \(\mathrm{KE}\).
Same subject
Explore more questions on app
From JEE Mains
Explore more questions on app