JEE Mains · Physics · STD 11 - 10.2 transmission of heat
A body takes \(4\, {min}\). to cool from \(61^{\circ} {C}\) to \(59^{\circ} {C}\). If the temperature of the surroundings is \(30^{\circ} {C}\), the time taken by the body to cool from \(51^{\circ} {C}\) to \(49^{\circ} {C}\) is \(....\,min\)
- A \(8\)
- B \(4\)
- C \(6\)
- D \(4\)
Answer & Solution
Correct Answer
(C) \(6\)
Step-by-step Solution
Detailed explanation
\(\frac{\Delta T }{\Delta t }= K \left( T _{ t }- T _{ s }\right)\) \(\frac{61-59}{4}= K \left(\frac{61+59}{2}-30\right)\) \(\frac{51-49}{ t }= K \left(\frac{51+49}{2}-30\right)\) \(\frac{ t }{4}=\frac{60-30}{50-30}=\frac{30}{20}\) \(t =6\) minutes
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