JEE Mains · Physics · STD 12 - Semicondutor electronics
- JEE Mains 2021
- Hard
- Numerical
For the given circuit, the power across zener diode is ..... \({mW}.\)

Pick an option to check your answer.
Answer & Solution
Correct Answer
(B) \(120\)
Step-by-step Solution
Detailed explanation
\({i}=\frac{10 {V}}{5 {k} \Omega}=2 \,{mA}\)
\({I}=\frac{14 {V}}{1 {k} \Omega}=14 \,{mA}\)
\(\therefore {I}_{z}=12\, {mA}\)
\(\therefore {P}={I}_{z} {V}_{z}=120\, {mW}\)
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