JEE Mains · Physics · STD 12 - 14. Semicondutor electronics
For the given circuit, the power across zener diode is ..... \({mW}.\)

- A \(140\)
- B \(120\)
- C \(260\)
- D \(160\)
Answer & Solution
Correct Answer
(B) \(120\)
Step-by-step Solution
Detailed explanation
\({i}=\frac{10 {V}}{5 {k} \Omega}=2 \,{mA}\) \({I}=\frac{14 {V}}{1 {k} \Omega}=14 \,{mA}\) \(\therefore {I}_{z}=12\, {mA}\) \(\therefore {P}={I}_{z} {V}_{z}=120\, {mW}\)
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