JEE Mains · Maths · STD 11 - 7. binomial theoram
The coefficient of \(x^{4}\) in the expansion of \(\left(1+x+x^{2}+x^{3}\right)^{6}\) in powers of \(x,\) is
- A \(116\)
- B \(118\)
- C \(120\)
- D \(124\)
Answer & Solution
Correct Answer
(C) \(120\)
Step-by-step Solution
Detailed explanation
\(\left(1+x+x^{2}+x^{3}\right)^{6}=\left((1+x)\left(1+x^{2}\right)\right)^{6}\) \(=(1+x)^{6}\left(1+x^{2}\right)^{6}\) \(=\sum_{ r =0}^{6}{ }^{6} C _{ r } x ^{ r } \sum_{ r =0}^{6}{ }^{6} C _{ t } x ^{2 t }\)…
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