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JEE Mains · Physics · STD 11 - Motion in straight line
  • JEE Mains 2024
  • Hard
  • MCQ

Two cars are travelling towards each other at speed of \(20 \mathrm{~m} \mathrm{~s}^{-1}\) each. When the cars are \(300 \mathrm{~m}\) apart, both the drivers apply brakes and the cars retard at the rate of \(2 \mathrm{~m} \mathrm{~s}^{-2}\). The distance between them when they come to rest is _______.

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Answer & Solution

Correct Answer

(C) \(100 \mathrm{~m}\)

Step-by-step Solution

Detailed explanation

\(\left|\overrightarrow{\mathrm{u}}_{\mathrm{BA}}\right|=40 \mathrm{~m} / \mathrm{s}\)

\(\left|\overrightarrow{\mathrm{a}}_{\mathrm{BA}}\right|=4 \mathrm{~m} / \mathrm{s}\)

\(\text { Apply }\left(\mathrm{v}^2=\mathrm{u}^2+2 \mathrm{as}\right)_{\text {relitive }}\)

\(\mathrm{O}=(40)^2+2(-4)(\mathrm{S})\)

\(\mathrm{S}=200 \mathrm{~m}\)

Remaining distance\(=300-200=100 \mathrm{~m}\)

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