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JEE Mains · Physics · STD 12 - 14. Semicondutor electronics

For a constant collector-emitter voltage of \(8\,V\), the collector current of a transistor reached to the value of \(6\,mA\) from \(4\,mA\), whereas base current changed from \(20\,\mu A\) to \(25\,\mu\,A\) value. If transistor is in active state, small signal current gain (current amplification factor) will be.

  1. A \(240\)
  2. B \(400\)
  3. C \(0.0025\)
  4. D \(200\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(400\)

Step-by-step Solution

Detailed explanation

\(3\,V_{C E}=8\,V = I _{ C }=6\,mA\) from \(4\,mA\) \(I _{ B }=20\, \mu A\) to \(25\, \mu A\) Current gain \(\beta_{ av }=\frac{ I _{ C }{ }^{\prime}- I _{ C }}{ I _{ B }{ }^{\prime}- I _{ B }}=\frac{2\, mA }{5\, \mu A }\)…
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