JEE Mains · Physics · STD 12 - 14. Semicondutor electronics
For a constant collector-emitter voltage of \(8\,V\), the collector current of a transistor reached to the value of \(6\,mA\) from \(4\,mA\), whereas base current changed from \(20\,\mu A\) to \(25\,\mu\,A\) value. If transistor is in active state, small signal current gain (current amplification factor) will be.
- A \(240\)
- B \(400\)
- C \(0.0025\)
- D \(200\)
Answer & Solution
Correct Answer
(B) \(400\)
Step-by-step Solution
Detailed explanation
\(3\,V_{C E}=8\,V = I _{ C }=6\,mA\) from \(4\,mA\) \(I _{ B }=20\, \mu A\) to \(25\, \mu A\) Current gain \(\beta_{ av }=\frac{ I _{ C }{ }^{\prime}- I _{ C }}{ I _{ B }{ }^{\prime}- I _{ B }}=\frac{2\, mA }{5\, \mu A }\)…
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