JEE Mains · Physics · STD 12 - Semicondutor electronics
- JEE Mains 2022
- Medium
- Numerical
For a constant collector-emitter voltage of \(8\,V\), the collector current of a transistor reached to the value of \(6\,mA\) from \(4\,mA\), whereas base current changed from \(20\,\mu A\) to \(25\,\mu\,A\) value. If transistor is in active state, small signal current gain (current amplification factor) will be.
Pick an option to check your answer.
Answer & Solution
Correct Answer
(B) \(400\)
Step-by-step Solution
Detailed explanation
\(3\,V_{C E}=8\,V = I _{ C }=6\,mA\) from \(4\,mA\)
\(I _{ B }=20\, \mu A\) to \(25\, \mu A\)
Current gain \(\beta_{ av }=\frac{ I _{ C }{ }^{\prime}- I _{ C }}{ I _{ B }{ }^{\prime}- I _{ B }}=\frac{2\, mA }{5\, \mu A }\)
\(\beta_{ av }=\frac{2}{5} \times 10^{3}=\frac{2000}{5}=400\)
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