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JEE Mains · Physics · STD 12 - Semicondutor electronics
  • JEE Mains 2022
  • Medium
  • Numerical

For a constant collector-emitter voltage of \(8\,V\), the collector current of a transistor reached to the value of \(6\,mA\) from \(4\,mA\), whereas base current changed from \(20\,\mu A\) to \(25\,\mu\,A\) value. If transistor is in active state, small signal current gain (current amplification factor) will be.

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Answer & Solution

Correct Answer

(B) \(400\)

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Detailed explanation

\(3\,V_{C E}=8\,V = I _{ C }=6\,mA\) from \(4\,mA\)

\(I _{ B }=20\, \mu A\) to \(25\, \mu A\)

Current gain \(\beta_{ av }=\frac{ I _{ C }{ }^{\prime}- I _{ C }}{ I _{ B }{ }^{\prime}- I _{ B }}=\frac{2\, mA }{5\, \mu A }\)

\(\beta_{ av }=\frac{2}{5} \times 10^{3}=\frac{2000}{5}=400\)

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