JEE Mains · Physics · STD 12 - 2. Electric potential and capacitance
Five positive charges each having charge q are placed at the vertices of a pentagon as shown in the figure. The electric potential (V) and the electric field \((\vec{E})\) at the center O of the pentagon due to these five positive charges are:
- A \(V=\frac{5 q}{4 \pi \varepsilon_0 r}\) and \(\vec{E}=0\)
- B \(V=\frac{5 q}{4 \pi \varepsilon_0 r}\) and \(\vec{E}=\frac{5 \sqrt{3} q}{8 \pi \varepsilon_0 r^2} \hat{r}\)
- C \(V=\frac{5 q}{4 \pi \varepsilon_0 r}\) and \(\vec{E}=\frac{5 q}{4 \pi \varepsilon_0 r^2} \hat{r}\)
- D \(V=0\) and \(\vec{E}=0\)
Answer & Solution
Correct Answer
(A) \(V=\frac{5 q}{4 \pi \varepsilon_0 r}\) and \(\vec{E}=0\)
Step-by-step Solution
Detailed explanation
Electric potential \(\rightarrow V =\frac{5 Kq }{ R }\) As regular polygon \( \rightarrow \vec{E}=0 \)
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