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JEE Mains · Physics · STD 12 - 14. Semicondutor electronics
Figure shows a circuit in which three identical diodes are used . Each diode has forward resistance of \(20\,\Omega \) and infinite backward resistance. Resistors \(R_1 = R_2 = R_3 = 50\,\Omega.\) Battery voltage is \(6\,V.\) The current through \(R_3\) is.....\(mA\)
- A 50
- B 100
- C 60
- D 25
Answer & Solution
Correct Answer
(A) 50
Step-by-step Solution
Detailed explanation
Here, diodes \(D_1\) and \(D_2\) are forward biased and \(D_3\) is reverse biased. Therefore current through \(R_3\) \(i = \frac{V}{{R'}} = \frac{6}{{120}} = \frac{1}{{20}}A = 50\,mA\)
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