JEE Mains · Physics · STD 12 - 10. Wave optics
In interference experiment the path difference between two interfering waves at a point \(A\) on the screen is \(\lambda/3\), where \(\lambda\) is the wavelength of these waves, and at another point \(B\) the path difference is \(\lambda/6\). The ratio of intensities at points \(A\) and \(B\) is _______.
- A \(3\)
- B \(4\)
- C \(1/3\)
- D \(1/4\)
Answer & Solution
Correct Answer
(C) \(1/3\)
Step-by-step Solution
Detailed explanation
The phase difference \(\Delta \phi\) is related to the path difference \(\Delta x\) by the relation \(\Delta \phi = \dfrac{2\pi}{\lambda} \Delta x\). For point \(A\), the path difference is \(\Delta x_A = \dfrac{\lambda}{3}\).…
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