JEE Mains · Physics · STD 11 - 11. thermodynamics
A thermodynamic system is taken from an original state \(D\) to an intermediate state \(E\) by the linear process shown in the figure. Its volume is then reduced to the original volume from \(E\) to \(F\) by an isobaric process. The total work done by the gas from \(D\) to \(E\) to \(F\) will be \(......J\)

- A \(-450\)
- B \(450\)
- C \(900\)
- D \(1350\)
Answer & Solution
Correct Answer
(B) \(450\)
Step-by-step Solution
Detailed explanation
\(W _{ DE }=\frac{1}{2}(600+300) 3\,J\) \(=1350\,J\) \(W _{ EF }=-300 \times 3=-900\,J\) \(W _{ DEF }=450\,J\)
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