JEE Mains · Physics · STD 12 - 8. Electromagnetic waves
A magnetic field vector in an electromagnetic wave is represented by \(\vec{B}=B_0\sin\left(2\pi vt-\dfrac{2\pi x}{\lambda}\right)\hat{j}\). Its associated electric field vector is ______.
- A \(\vec{E}=-v\lambda B_0\sin\left(2\pi vt-\dfrac{2\pi x}{\lambda}\right)\hat{k}\)
- B \(\vec{E}=-v\lambda B_0\sin\left(2\pi vt-\dfrac{2\pi x}{\lambda}\right)\hat{i}\)
- C \(\vec{E}=v\lambda B_0\sin\left(2\pi vt-\dfrac{2\pi x}{\lambda}\right)\hat{k}\)
- D \(\vec{E}=v\lambda B_0\sin\left(2\pi vt-\dfrac{2\pi x}{\lambda}\right)\hat{i}\)
Answer & Solution
Correct Answer
(A) \(\vec{E}=-v\lambda B_0\sin\left(2\pi vt-\dfrac{2\pi x}{\lambda}\right)\hat{k}\)
Step-by-step Solution
Detailed explanation
The direction of propagation of the electromagnetic wave is determined by the phase term \(2\pi vt - \dfrac{2\pi x}{\lambda}\), which indicates that the wave is travelling along the \(+x\) direction (\(\hat{i}\)). The direction of the magnetic field \(\vec{B}\) is given as…
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