JEE Mains · Physics · STD 11 - 3.1 vectors
The resultant of these forces \(\overrightarrow{O P}, \overrightarrow{O Q}, \overrightarrow{O R}, \overrightarrow{O S}\) and \(\overrightarrow{{OT}}\) is approximately \(\ldots \ldots {N}\). [Take \(\sqrt{3}=1.7, \sqrt{2}=1.4\) Given \(\hat{{i}}\) and \(\hat{{j}}\) unit vectors along \({x}, {y}\) axis \(]\)

- A \(9.25 \hat{{i}}+5 \hat{{j}}\)
- B \(3 \hat{{i}}+15 \hat{{j}}\)
- C \(2.5 \hat{i}-14.5 \hat{{j}}\)
- D \(-1.5 \hat{{i}}-15.5 \hat{{j}}\)
Answer & Solution
Correct Answer
(A) \(9.25 \hat{{i}}+5 \hat{{j}}\)
Step-by-step Solution
Detailed explanation
\(\hat{F}_{x}=\left(10 \times \frac{\sqrt{3}}{2}+20\left(\frac{1}{2}\right)+20\left(\frac{1}{\sqrt{2}}\right)-15\left(\frac{1}{\sqrt{2}}\right)-15\left(\frac{\sqrt{3}}{2}\right)\right) \hat{i}\) \(=9.25 \hat{i}\)…
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