JEE Mains · Physics · STD 11 - Vectors
- JEE Mains 2021
- Medium
- MCQ
The resultant of these forces \(\overrightarrow{O P}, \overrightarrow{O Q}, \overrightarrow{O R}, \overrightarrow{O S}\) and \(\overrightarrow{{OT}}\) is approximately \(\ldots \ldots {N}\). [Take \(\sqrt{3}=1.7, \sqrt{2}=1.4\) Given \(\hat{{i}}\) and \(\hat{{j}}\) unit vectors along \({x}, {y}\) axis \(]\)
Pick an option to check your answer.
Answer & Solution
Correct Answer
(A) \(9.25 \hat{{i}}+5 \hat{{j}}\)
Step-by-step Solution
Detailed explanation
\(\hat{F}_{x}=\left(10 \times \frac{\sqrt{3}}{2}+20\left(\frac{1}{2}\right)+20\left(\frac{1}{\sqrt{2}}\right)-15\left(\frac{1}{\sqrt{2}}\right)-15\left(\frac{\sqrt{3}}{2}\right)\right) \hat{i}\)
\(=9.25 \hat{i}\)
\(\vec{F}_{y}=\left(15\left(\frac{1}{2}\right)+20\left(\frac{\sqrt{3}}{2}\right)+10\left(\frac{1}{2}\right)-15\left(\frac{1}{\sqrt{2}}\right)-20\left(\frac{1}{\sqrt{2}}\right)\right) \hat{j}\)
\(=5 \hat{j}\)
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