JEE Mains · Physics · STD 12 - Nuclei
- JEE Mains 2024
- Hard
- MCQ
In a hypothetical fission reaction \({ }_{92} \mathrm{X}^{236} \rightarrow{ }_{56} \mathrm{Y}^{141}+{ }_{36} \mathrm{Z}^{92}+3 \mathrm{R}\) The identity of emitted particles \((R)\) is _______.
Pick an option to check your answer.
Answer & Solution
Correct Answer
(C) Neutron
Step-by-step Solution
Detailed explanation
\(\mathrm{Z} \text { in LHS }=92\)
\(\mathrm{Z} \text { in } \mathrm{RHS}=56+36=92\)
\(\mathrm{~A} \text { in } \mathrm{LHS}=236\)
\(\mathrm{~A} \text { in } \mathrm{RHS}=141+92=233\)
So \(3\) neutrons are released.
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