JEE Mains · Physics · STD 11 - 11. thermodynamics
An ideal gas goes from an initial state to final state. During the process, the pressure of gas increases linearly with temperature.
A. The work done by gas during the process is zero.
B. The heat added to gas is different from change in its internal energy.
C. The volume of the gas is increased.
D. The internal energy of the gas is increased.
E. The process is isochoric (constant volume process)
Choose the correct answer from the options given below:
- A E Only
- B A, B, C, D Only
- C A, D, E Only
- D A, C Only
Answer & Solution
Correct Answer
(C) A, D, E Only
Step-by-step Solution
Detailed explanation
Given that \(\mathrm{P}=\mathrm{kT}\) \(\frac{\mathrm{P}}{\mathrm{~T}}=\text { constant }\) \(\therefore\) Volume is constant or isochoric process. \(\begin{aligned} & \therefore \mathrm{W}_{\mathrm{D}}=0 \\ & \therefore \mathrm{Q}=\Delta \mathrm{U} \end{aligned}\) Also…
See the Complete Solution
Get step-by-step explanations for this and 2.5 Lakh+ more JEE, NEET & CET questions.
- Unlock all solutions
- Practice the full chapter
- Track accuracy across PYQs
4.8 rated on Google Play · 14,000+ reviews
More questions from Physics
- A coil of negligible resistance is connected in series with \(90 \Omega\) resistor across \(120 \mathrm{~V}, 60 \mathrm{~Hz}\) supply. A voltmeter reads \(36 \mathrm{~V}\) across resistance. Inductance of the coil is _______.JEE Mains 2024 Hard
- When two resistance \(R_1\) and \(R_2\) connected in series and introduced into the left gap of a meter bridge and a resistance of \(10 \Omega\) is introduced into the right gap, a null point is found at \(60 cm\) from left side. When \(R_1\) and \(R_2\) are connected in parallel and introduced into the left gap, a resistance of \(3 \Omega\) is introduced into the right-gap to get null point at 40 cm from left end. The product of \(R_1 R_2\) is \(.............\Omega\)JEE Mains 2023 Hard
- The disintegration rate of a certain radioactive sample at any instant is \(4250\) disintegrations per minute.\(10\) minutes later, the rate becomes \(2250\) disintegrations per minute. The approximate decay cons \(.........\min^{-1}\)JEE Mains 2022 Medium
- A scientist is observing a bacteria through a compound microscope. For better analysis and to improve its resolving power he should. (Select the best option)JEE Mains 2023 Medium
- The radius of a nucleus of mass number \(64\) is \(4.8\) fermi. Then the mass number of another nucleus having radius of \(4\) fermi is \(\frac{1000}{x}\), where \(x\) is _______.JEE Mains 2024 Hard
- In the following circuit, the correct relation between output \(( Y )\) and inputs \(A\) and \(B\) will be
JEE Mains 2022 Hard
More PYQs from JEE Mains
- Two point charges of 1 nC and 2 nC are placed at the two corners of equilateral triangle of side 3 cm. The work done in bringing a charge of 3 nC from infinity to the third corner of the triangle is ________ \(\mu\)J.
(\(\frac{1}{4\pi\epsilon_{0}} = 9 \times 10^{9}\ N.m^{2}/C^{2}\))JEE Mains 2026 Hard - Consider \(10\) observation \(\mathrm{x}_1, \mathrm{x}_2, \ldots, \mathrm{x}_{10}\). such that \(\sum_{i=1}^{10}\left(x_i-\alpha\right)=2\) and \(\sum_{i=1}^{10}\left(x_i-\beta\right)^2=40\), where \(\alpha, \beta\) are positive integers. Let the mean and the variance of the observations be \(\frac{6}{5}\) and \(\frac{84}{25}\) respectively. The \(\frac{\beta}{\alpha}\) is equal to :JEE Mains 2024 Hard
- A galvanometer has a resistance of \(50 \Omega\) and allows a maximum current of \(5 \mathrm{~mA}\) to pass. What is the necessary series resistance to connect to convert it to a voltmeter that can measure \(100 \mathrm{~V}\)?JEE Mains 2024 Hard
- Let \({a_1},{a_2},\;.\;.\;.\;.,{a_{49}}\) be in \(A.P.\) such that \(\mathop \sum \limits_{k = 0}^{12} {a_{4k + 1}} = 416\) and \({a_9} + {a_{43}} = 66\). If \(a_1^2 + a_2^2 + \ldots + a_{17}^2 = 140m,\) then \(m = \;\;..\;.\;.\;.\;\)JEE Mains 2018 Hard
- If \(z \) is a complex number of unit modulus and argument \(\theta\), then \({\rm{arg}}\left( {\frac{{1 + z}}{{1 + (\bar z)}}} \right)\) equals.JEE Mains 2013 Medium
- If \(\mathrm{y}(\alpha)=\sqrt{2\left(\frac{\tan \alpha+\cot \alpha}{1+\tan ^{2} \alpha}\right)+\frac{1}{\sin ^{2} \alpha}}, \alpha \in\left(\frac{3 \pi}{4}, \pi\right)\) then \(\frac{d y}{d \alpha}\) at \(\alpha=\frac{5 \pi}{6}\) isJEE Mains 2020 Hard