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JEE Mains · Physics · STD 12 - Current electricity
  • JEE Mains 2022
  • Medium
  • MCQ

Given below are two statements: Statement \(I\) : A uniform wire of resistance \(80\,\Omega\) is cut into four equal parts. These parts are now connected in parallel. The equivalent resistance of the combination will be \(5\,\Omega\). Statement \(II :\) Two resistance \(2\,R\) and \(3\,R\) are connected in parallel in a electric circuit. The value of thermal energy developed in \(3\,R\) and \(2\,R\) will be in the ratio \(3:2.\) In the light of the above statements, choose the most appropriate answer from the options given below

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Answer & Solution

Correct Answer

(C) Statement \(I\) is correct but statement \(II\) is incorrect.

Step-by-step Solution

Detailed explanation

Statement \(1- R =80\,\Omega\)

\(R _{1}= R _{2}= R _{3}= R _{4}=20\,\Omega\)

Statement \(2-\)

\(P _{ th }=\frac{ v ^{2}}{ R }\)

\(\frac{P_{1}}{P_{2}}=\left(\frac{R_{2}}{R_{1}}\right)=\frac{2}{3}\) (where \(P\) is power)

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