JEE Mains · Physics · STD 12 - 3. current electricity
Given below are two statements: Statement \(I\) : A uniform wire of resistance \(80\,\Omega\) is cut into four equal parts. These parts are now connected in parallel. The equivalent resistance of the combination will be \(5\,\Omega\). Statement \(II :\) Two resistance \(2\,R\) and \(3\,R\) are connected in parallel in a electric circuit. The value of thermal energy developed in \(3\,R\) and \(2\,R\) will be in the ratio \(3:2.\) In the light of the above statements, choose the most appropriate answer from the options given below
- A Both statement \(I\) and statement \(II\) are correct
- B Both statement \(I\) and statement \(II\) are incorrect
- C Statement \(I\) is correct but statement \(II\) is incorrect.
- D Statement \(I\) is incorrect but statement \(II\) is correct.
Answer & Solution
Correct Answer
(C) Statement \(I\) is correct but statement \(II\) is incorrect.
Step-by-step Solution
Detailed explanation
Statement \(1- R =80\,\Omega\) \(R _{1}= R _{2}= R _{3}= R _{4}=20\,\Omega\) Statement \(2-\) \(P _{ th }=\frac{ v ^{2}}{ R }\) \(\frac{P_{1}}{P_{2}}=\left(\frac{R_{2}}{R_{1}}\right)=\frac{2}{3}\) (where \(P\) is power)
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