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JEE Mains · Physics · STD 12 - Electric potential and capacitance
  • JEE Mains 2022
  • Medium
  • MCQ

An \(\alpha\) particle and a proton are accelerated from rest through the same potential difference. The ratio of linear momenta acquired by above two particals will be.

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Answer & Solution

Correct Answer

(B) \(2 \sqrt{2}: 1\)

Step-by-step Solution

Detailed explanation

\(p =\sqrt{2 mE }=\sqrt{2 mqV }\)

\(\frac{ p _{\alpha}}{ p _{ p }}=\sqrt{\frac{ m _{\alpha} q _{\alpha}}{ m _{ p } q _{ p }}}=\sqrt{\frac{4}{1} \times \frac{2}{1}}\)

\(=\frac{2 \sqrt{2}}{1}\)

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