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JEE Mains · Physics · STD 11 - 6. system of particles and rotational motion

A circular disc reaches from top to bottom of an inclined plane of length \(l\). When it slips down the plane, if takes \(\mathrm{t} \mathrm{s}\). When it rolls down the plane then it takes \(\left(\frac{\alpha}{2}\right)^{1 / 2} \mathrm{t} s\), where \(\alpha\) is. _______.

  1. A \(3\)
  2. B \(4\)
  3. C \(5\)
  4. D \(6\)
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Answer & Solution

Correct Answer

(A) \(3\)

Step-by-step Solution

Detailed explanation

For slipping \(\mathrm{a}=\mathrm{g} \sin \theta\) \(\ell=\frac{1}{2} \mathrm{at}^2 \Rightarrow \mathrm{t}=\sqrt{\frac{2 \ell}{\mathrm{g} \sin \theta}}\) For rolling…
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