JEE Mains · Physics · STD 11 - 9.1 fluid mechanics
Water flows through a horizontal tube as shown in the figure. The difference in height between the water columns in vertical tubes is 5 cm and the area of cross-sections at \(A\) and \(B\) are \(6 cm^2\) and \(3 cm^2\) respectively.
The rate of flow will be ___________ \(cm ^3 / s\). (take \(g =10 m / s ^2\) )
- A \( \frac{200}{\sqrt{3}} \)
- B \( 200\sqrt{6} \)
- C \( 200\sqrt{3} \)
- D \( 100\sqrt{3} \)
Answer & Solution
Correct Answer
(C) \( 200\sqrt{3} \)
Step-by-step Solution
Detailed explanation
From continuity equation \( A_{A}V_{A} = A_{B}V_{B} \Rightarrow 6V_{A} = 3V_{B} \Rightarrow V_{B} = 2V_{A} \) Applying Bernoullis equation between A & B, \( P_{A} + \frac{1}{2}\rho V_{A}^{2} = P_{B} + \frac{1}{2}\rho V_{B}^{2} \)…
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