JEE Mains · Physics · STD 12 - 9. Ray optics and optical instruments
An object ' \(o\) ' is placed at a distance of \(100\,cm\) in front of a concave mirror of radius of curvature \(200\,cm\) as shown in the figure. The object starts moving towards the mirror at a speed \(2\,cm / s\). The position of the image from the mirror after \(10\,s\) will be at ...... \(cm\).
- A \(40\)
- B \(405\)
- C \(402\)
- D \(400\)
Answer & Solution
Correct Answer
(D) \(400\)
Step-by-step Solution
Detailed explanation
After \(10\,sec\). \(u =-80\,cm\) \(f =-100\,cm\) \(\frac{1}{ v }+\frac{1}{ u }=\frac{1}{ f }\) \(v =400\,cm\)
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