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JEE Mains · Physics · STD 12 -Alternating current
  • JEE Mains 2021
  • Hard
  • MCQ

An \(AC\) current is given by \(I = I _{1} \sin \omega t + I _{2} \cos \omega t\). A hot wire ammeter will give a reading

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Answer & Solution

Correct Answer

(B) \(\sqrt{\frac{ I _{1}^{2}+ I _{2}^{2}}{2}}\)

Step-by-step Solution

Detailed explanation

\(I=I_{1} \sin \omega t+I_{2} \cos \omega t\)

\(\therefore I_{0}=\sqrt{I_{1}^{2}+I_{2}^{2}}\)

\(\therefore I_{ rms }=\frac{I_{0}}{\sqrt{2}}=\sqrt{\frac{I_{1}^{2}+I_{2}^{2}}{2}}\)

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