JEE Mains · Maths · STD 12 - 9. differential equations
Let \(y = y ( x )\) be the solution of the differential equation \(\left( x ^2-3 y ^2\right) dx +3 xy dy =0, y (1)=1\). Then \(6 y^2(e)\) is equal to
- A \(3 e ^2\)
- B \(e ^2\)
- C \(2 e ^2\)
- D \(\frac{3 e ^2}{2}\)
Answer & Solution
Correct Answer
(C) \(2 e ^2\)
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