JEE Mains · Physics · STD 11 - 4.2 friction
A uniform chain of \(6\, m\) length is placed on a table such that a part of its length is hanging over the edge of the table. The system is at rest. The co-efficient of static friction between the chain and the surface of the table is \(0.5\), the maximum length of the chain hanging from the table is.......\(m.\)
- A \(25\)
- B \(12\)
- C \(9\)
- D \(2\)
Answer & Solution
Correct Answer
(D) \(2\)
Step-by-step Solution
Detailed explanation
Mass per unit length \(=\lambda\) \(N = mg =\lambda( L - x ) g\) \(fs _{\max }=\mu_{ s } N\) \(fs _{\max }=(0.5)(\lambda)( L - x ) g\) And also \(fs _{\max }= m _{ x } g\) \(0.5 \lambda( L - x ) g =\lambda xg\) \(\frac{ L - x }{2}= x\)…
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