JEE Mains · Physics · STD 11 - Friction
- JEE Mains 2022
- Medium
- Numerical
A uniform chain of \(6\, m\) length is placed on a table such that a part of its length is hanging over the edge of the table. The system is at rest. The co-efficient of static friction between the chain and the surface of the table is \(0.5\), the maximum length of the chain hanging from the table is.......\(m.\)
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Answer & Solution
Correct Answer
(D) \(2\)
Step-by-step Solution
Detailed explanation
Mass per unit length \(=\lambda\)
\(N = mg =\lambda( L - x ) g\)
\(fs _{\max }=\mu_{ s } N\)
\(fs _{\max }=(0.5)(\lambda)( L - x ) g\)
And also \(fs _{\max }= m _{ x } g\)
\(0.5 \lambda( L - x ) g =\lambda xg\)
\(\frac{ L - x }{2}= x\)
\(\frac{ L }{2}=\frac{3 x }{2} \Rightarrow x =\frac{ L }{3}=\frac{6}{3}=2 \,m\)
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