JEE Mains · Physics · STD 12 - 9. Ray optics and optical instruments
Two plane mirrors \({M}_{1}\) and \({M}_{2}\) are at right angle to each other shown. A point source \('P'\) is placed at \('a'\) and \('2a'\) meter away from \({M}_{1}\) and \({M}_{2}\) respectively. The longest distance between the images thus formed is : (Take \(\sqrt{5}=2.3\) )
- A \(3 {a}\)
- B \(4.6 {a}\)
- C \(2.3 {a}\)
- D \(2 \sqrt{10} {a}\)
Answer & Solution
Correct Answer
(B) \(4.6 {a}\)
Step-by-step Solution
Detailed explanation
Shortest distance is \(2 {a}\) between \({I}_{1} \& {I}_{3}\) But answer given is for \({I}_{1} \& {I}_{2}\) \(\sqrt{(4 a)^{2}+(2 a)^{2}}\) \(a \sqrt{20}\) \(4.47 {a}\)
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