JEE Mains · Physics · STD 11 - 9.1 fluid mechanics
An ideal fluid of density \(800 \; kgm ^{-3}\), flows smoothly through a bent pipe (as shown in figure) that tapers in cross-sectional area from \(a\) to \(\frac{ a }{2}\). The pressure difference between the wide and narrow sections of pipe is \(4100 \; Pa\). At wider section, the velocity of fluid is \(\frac{\sqrt{x}}{6} \; ms ^{-1}\) for \(x = \dots\) \(\left(\right.\) Given \(g =10 \; m ^{-2}\) )
- A \(363\)
- B \(373\)
- C \(383\)
- D \(393\)
Answer & Solution
Correct Answer
(A) \(363\)
Step-by-step Solution
Detailed explanation
From continuity equation \(a v _{1}=\frac{ a }{2} v _{2}\) \(v _{2}=2 v _{1}\) From Bernoulli's theorem, \(P _{1}+\rho g h_{1}+\frac{1}{2} \rho v _{1}^{2}= P _{2}+\rho g h_{2}+\frac{1}{2} \rho v _{2}^{2}\)…
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