JEE Mains · Physics · STD 11 - 6. system of particles and rotational motion
A solid sphere of mass 5 kg and radius 10 cm is kept in contact with another solid sphere of mass 10 kg and radius 20 cm. The moment of inertia of this pair of spheres about the tangent passing through the point of contact is __________ \( kg.m^{2} \).
- A 0.36
- B 0.72
- C 0.18
- D 0.63
Answer & Solution
Correct Answer
(D) 0.63
Step-by-step Solution
Detailed explanation
\( I=\frac{7}{5}[m_{1}R_{1}^{2}+m_{2}R_{2}^{2}] \) \( =\frac{7}{5}[5(10)^{2}+10\times(20)^{2}]\times10^{-4} \) \( I=63\times10^{-2}kg~m^{2} \) \( I=0.63~kg~m^{2} \)
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