JEE Mains · Physics · STD 11 - 4.2 friction
In the given arrangement of a doubly inclined plane two blocks of masses \(\mathrm{M}\) and \(\mathrm{m}\) are placed. The blocks are connected by a light string passing over an ideal pulley as shown. The coefficient of friction between the surface of the plane and the blocks is \(0.25\) . The value of \(\mathrm{m}\), for which \(\mathrm{M}=10\) \(\mathrm{kg}\) will move down with an acceleration of \(2 \mathrm{~m} / \mathrm{s}^2\), is _______. (take \(\mathrm{g}=10 \mathrm{~m} / \mathrm{s}^2\) and \(\left.\tan 37^{\circ}=3 / 4\right)\)
- A \(9 \mathrm{~kg}\)
- B \(4.5 \mathrm{~kg}\)
- C \(6.5 \mathrm{~kg}\)
- D \(2.25 \mathrm{~kg}\)
Answer & Solution
Correct Answer
(B) \(4.5 \mathrm{~kg}\)
Step-by-step Solution
Detailed explanation
For M block \(10 \mathrm{~g} \sin 53^{\circ}-\mu(10 \mathrm{~g}) \cos 53^{\circ}-\mathrm{T}=10 \times 2\) \(\mathrm{~T}=80-15-20\) \(\mathrm{~T}=45 \mathrm{~N}\) For \(\mathrm{m}\) block…
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