JEE Mains · Physics · STD 12 - 1. Electric charges and fields
If a charge \(q\) is placed at the centre of a closed hemispherical non-conducting surface, the total flux passing through the flat surface would be
- A \(\frac{q}{\varepsilon_{0}}\)
- B \(\frac{q}{2 \varepsilon_{0}}\)
- C \(\frac{q}{4 \varepsilon_{0}}\)
- D \(\frac{ q }{2 \pi \varepsilon_{0}}\)
Answer & Solution
Correct Answer
(B) \(\frac{q}{2 \varepsilon_{0}}\)
Step-by-step Solution
Detailed explanation
Total flux through complete spherical surface is \(\frac{ q }{\varepsilon_{0}}\) So the flux through curved surface will be \(\frac{q}{2 \varepsilon_{0}}\). The flux through flat surface will be zero. Remark : Electric flux through flat surface is zero but no option is given,…
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