JEE Mains · Physics · STD 12 -6. Electromagnetic induction
A thin strip \(10\, cm\) long is on a \(U\) shaped wire of negligible resistance and it is connected to a spring of spring constant \(0.5\,Nm^{-1}\) (see figure). The assembly is kept in a uniform magnetic field of \(0.1\, T\). If the strip is pulled from its equilibrium position and released, the number of oscillations it performs before its amplitude decreases by a factor of \(e\) is \(N\). If the mass of the strip is \(50\, grams\), its resistance \(10\,\Omega \) and air drag negligible, \(N\) will be close to
- A \(50000\)
- B \(10000\)
- C \(1000\)
- D \(5000\)
Answer & Solution
Correct Answer
(D) \(5000\)
Step-by-step Solution
Detailed explanation
\(\mathrm{T}_{0}=2 \pi \sqrt{\frac{\mathrm{m}}{\mathrm{k}}}=\frac{2 \pi}{\sqrt{10}}\) \(\mathrm{A}=\mathrm{A}_{0} \mathrm{e}^{-1 / \gamma}\) \(\therefore\) for \(\mathrm{A}=\frac{\mathrm{A}_{0}}{\mathrm{e}}, \mathrm{t}=\gamma\)…
See the Complete Solution
Get step-by-step explanations for this and 2.5 Lakh+ more JEE, NEET & CET questions.
- Unlock all solutions
- Practice the full chapter
- Track accuracy across PYQs
4.8 rated on Google Play · 14,000+ reviews
More questions from Physics
- The reverse breakdown voltage of a Zener diode is \(5.6\, V\) in the given circuit. The current \(I_z\) through the Zener is......\(mA\)
JEE Mains 2019 Hard - A solid sphere of radius \(R\) gravitationally attracts a particle placed at \(3 R\) form its centre with a force \(F _{1}\). Now a spherical cavity of radius \(\left(\frac{ R }{2}\right)\) is made in the sphere (as shown in figure) and the force becomes \(F _{2}\). The value of \(F _{1}: F _{2}\) is
JEE Mains 2021 Hard - Consider a situation in which a ring, a solid cylinder and a solid sphere roll down on the same inclined plane without slipping. Assume that they start rolling from rest and having identical diameter. The correct statement for this situation is:-JEE Mains 2021 Medium
- If \(Z=\frac{A^{2} B^{3}}{C^{4}}\), then the relative error in \(Z\) will beJEE Mains 2022 Easy
- Two very long, straight and insulated wires are kept at \(90^o\) angle from each other In \(xy -\) plane as shown in the figure. These wires carry current of equal magnitude \(I\), whose directions are shown in the figure. The net magnetic field at point \(P\) will be
JEE Mains 2019 Medium - As per given figure, a weightless pulley \(P\) is attached on a double inclined frictionless surface. The tension in the string (massless) will be (if \(g=\) \(10\,m / s ^2\) )
JEE Mains 2023 Medium
More PYQs from JEE Mains
- Let the line \(2 \mathrm{x}+3 \mathrm{y}-\mathrm{k}=0, \mathrm{k}>0\), intersect the \(\mathrm{x}\)-axis and \(\mathrm{y}\)-axis at the points \(\mathrm{A}\) and \(\mathrm{B}\), respectively. If the equation of the circle having the line segment \(\mathrm{AB}\) as a diameter is \(\mathrm{x}^2+\mathrm{y}^2-3 \mathrm{x}-2 \mathrm{y}=0\) and the length of the latus rectum of the ellipse \(\mathrm{x}^2+9 \mathrm{y}^2=\mathrm{k}^2\) is \(\frac{\mathrm{m}}{\mathrm{n}}\), where \(\mathrm{m}\) and \(\mathrm{n}\) are coprime, then \(2 \mathrm{~m}+\mathrm{n}\) is equal toJEE Mains 2024 Hard
- A proton and a deutron ( \(\mathrm{q}=+\mathrm{e}, m=2.0 \mathrm{u})\) having same kinetic energies enter a region of uniform magnetic field \(\vec{B}\), moving perpendicular to \(\vec{B}\). The ratio of the radius \(r_d\) of deutron path to the radius \(r_p\) of the proton path is _______.JEE Mains 2024 Hard
- The ordered pair \((a, b)\), for which the system of linear equations \(3 x-2 y+z=b\) ; \(5 x-8 y+9 z=3\) ; \(2 x+y+a z=-1\) has no solution, isJEE Mains 2022 Medium
- In free space, an electromagnetic wave of \(3 \; GHz\) of \(3 \; GHz\) frequency strikes over the edge of an object of size \(\frac{\lambda}{100}\), where \(\lambda\) is the wavelength of the wave in free space. The phenomenon, which happens there will be .....JEE Mains 2022 Hard
- If \(b _{ n }=\int \limits_{0}^{\frac{\pi}{2}} \frac{\cos ^{2} nx }{\sin x } dx , n \in N\), thenJEE Mains 2022 Hard
- If \(\alpha=\lim _{x \rightarrow \pi / 4} \frac{\tan ^{3} x-\tan x}{\cos \left(x+\frac{\pi}{4}\right)}\) and \(\beta=\lim _{x \rightarrow 0}(\cos x)^{\operatorname{cotx}}\) are the roots of the equation, \(a x^{2}+b x-4=0\), then the ordered pair \((\mathrm{a}, \mathrm{b})\) is :JEE Mains 2021 Hard