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JEE Mains · Physics · STD 12 - 8. Electromagnetic waves
If the magnetic field of a plane electromagnetic wave is given by (The speed of light \( = 3 \times {10^8}\,m/s\) ) \(B = 100 \times {10^{ - 6}}\,\sin \,\left[ {2\pi \times 2 \times {{10}^{15}}\,\left( {t - \frac{x}{c}} \right)} \right]\) then the maximum electric field associated with it is
- A \(6 \times {10^4}\,N/C\)
- B \(3 \times {10^4}\,N/C\)
- C \(4 \times {10^4}\,N/C\)
- D \(4.5 \times {10^4}\,N/C\)
Answer & Solution
Correct Answer
(B) \(3 \times {10^4}\,N/C\)
Step-by-step Solution
Detailed explanation
\(E_{0}=B_{0} \times C\) \(=100 \times 10^{-6} \times 3 \times 10^{8}\) \(=3 \times 10^{4} \,N / C\)
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