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JEE Mains · Physics · STD 11 - Units,dimensions and measurement
  • JEE Mains 2023
  • Medium
  • Numerical

A cylindrical wire of mass \((0.4 \pm 0.01)\,g\) has length \((8 \pm 0.04)\,cm\) and radius \((6 \pm 0.03)\,mm\).The maximum error in its density will be \(......\,\%\)

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Correct Answer

(C) 4

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Detailed explanation

\(\rho=\frac{ m }{\pi r ^2 l} \Rightarrow\left|\frac{ d \rho}{\rho}\right|_{\max }=\left|\frac{ dm }{ m }\right|+2\left|\frac{ dr }{ r }\right|+\left|\frac{ d l}{l}\right|\)

\(=\frac{0.01}{0.4}+\frac{2(0.03)}{6}+\frac{0.04}{8}\)

\(\Rightarrow \% \text { error in density }=\left(\frac{ d \rho}{\rho}\right) \times 100 \%\)

\(=(2.5+1+0.5) \%=4 \%\)

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