JEE Mains · Physics · STD 11 - Units,dimensions and measurement
- JEE Mains 2023
- Medium
- Numerical
A cylindrical wire of mass \((0.4 \pm 0.01)\,g\) has length \((8 \pm 0.04)\,cm\) and radius \((6 \pm 0.03)\,mm\).The maximum error in its density will be \(......\,\%\)
Pick an option to check your answer.
Answer & Solution
Correct Answer
(C) 4
Step-by-step Solution
Detailed explanation
\(\rho=\frac{ m }{\pi r ^2 l} \Rightarrow\left|\frac{ d \rho}{\rho}\right|_{\max }=\left|\frac{ dm }{ m }\right|+2\left|\frac{ dr }{ r }\right|+\left|\frac{ d l}{l}\right|\)
\(=\frac{0.01}{0.4}+\frac{2(0.03)}{6}+\frac{0.04}{8}\)
\(\Rightarrow \% \text { error in density }=\left(\frac{ d \rho}{\rho}\right) \times 100 \%\)
\(=(2.5+1+0.5) \%=4 \%\)
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