JEE Mains · Physics · STD 12 - 13. Nuclei
The binding energy for the following nuclear reactions are expressed in MeV .
\({ }_2 He ^3+{ }_0 n ^1 \rightarrow{ }_2 He ^4+20 MeV\)
\({ }_2 He ^4+{ }_0 n ^1 \rightarrow{ }_2 He ^5-0.9 MeV\)
If \(X _3, X _4, X _5\) denote the stability of \({ }_2 He ^3,{ }_2 He ^4\) and \({ }_2 He ^5\), respectively, then the correct order is :
- A \(X_4>X_5>X_3\)
- B \(X_{4}=X_{5}=X_{3}\)
- C \(X_{4} > X_{5} < X_{3}\)
- D \(X_{4} < X_{5} < X_{3}\)
Answer & Solution
Correct Answer
(A) \(X_4>X_5>X_3\)
Step-by-step Solution
Detailed explanation
\(BE_{He^{4}}-BE_{He^{3}}=20MeV\) ...(1) \(BE_{He^{5}}-BE_{He^{4}}=-0.9MeV\) ...(2) From eq (1) & (2) \(BE_{He^{4}}>BE_{He^{5}}>BE_{He^{3}}\) \(X_{4}>X_{5}>X_{3}\)
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