JEE Mains · Physics · STD 12 -6. Electromagnetic induction
A square loop of side \(2\) cm is placed in a time varying magnetic field with magnitude as \(B = 0.4\sin(300t)\) Tesla. The normal to the plane of loop makes an angle of \(60°\) with the field. The maximum induced emf produced in the loop is __________ mV.
- A \(12\)
- B \(18\)
- C \(21\)
- D \(24\)
Answer & Solution
Correct Answer
(D) \(24\)
Step-by-step Solution
Detailed explanation
Given: Side of the square loop, \(a = 2\) cm \(= 2 \times 10^{-2}\) m Area of the loop, \(A = a^2 = 4 \times 10^{-4}\) m\(^2\) Magnetic field, \(B = 0.4 \sin(300t)\) T Angle between the normal to the plane and the magnetic field, \(\theta = 60^\circ\) The magnetic flux through…
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