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JEE Mains · Physics · STD 12 - Ray optics and optical instruments
  • JEE Mains 2015
  • Medium
  • MCQ

You are asked to design a shaving mirror assuming that a person keeps it \(10\,cm\) from his face and views the magnified image of the face at the closest comfortable distance of \(25\,cm.\) The radius of curvature of the mirror would then be.....\(cm\)

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Answer & Solution

Correct Answer

(C) \(-60\)

Step-by-step Solution

Detailed explanation

convex mirror is used as a shaving mirror.

From question \(: v=15\, \mathrm{cm}, u=-10\,\mathrm{cm}\)

Radius of curvature, \(R=2\,\,f=?\)

Using mirror formula, \(\frac{1}{v}+\frac{1}{u}=\frac{1}{f}\)

\(\frac{1}{15}+\frac{1}{(-10)}=\frac{1}{f} \Rightarrow f=-30\, \mathrm{cm}\)

Therefore radius of curvature,

\(R=2\, \,f=-\,60\, \mathrm{cm}\)

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