JEE Mains · Physics · STD 12 - 9. Ray optics and optical instruments
A spherical surface separates two media of refractive indices 1 and 1.5 as shown in figure. Distance of the image of an object ' O ' is :
( C is the center of curvature of the spherical surface and \(R\) is the radius of curvature)
- A 0.24 m right to the spherical surface
- B 0.4 m left to the spherical surface
- C 0.24 m left to the spherical surface
- D 0.4 m right to the spherical surface
Answer & Solution
Correct Answer
(B) 0.4 m left to the spherical surface
Step-by-step Solution
Detailed explanation
\begin{aligned} & \frac{\mu_2}{\mathrm{v}}-\frac{\mu_1}{\mathrm{u}}=\frac{\mu_2-\mu_1}{\mathrm{R}} \\ & \frac{1.5}{\mathrm{v}}-\frac{1}{(-0.2)}=\frac{1.5-1}{0.4} \\ & \frac{1.5}{\mathrm{v}}=\frac{0.5}{0.4}-\frac{1}{0.2} \\ & \frac{1.5}{\mathrm{v}}=-\frac{1.5}{0.4} \\ &…
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