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JEE Mains · Maths · STD 12 - 5. continuity and differentiation

The derivative of \({\tan ^{ - 1}}\left( {\frac{{\sin \,x - \cos \,x}}{{\sin \,x + \cos \,x}}} \right)\), with respect to \(\frac{x}{2}\), where \(\left( {x \in \left( {0,\frac{\pi }{2}} \right)} \right)\) is

  1. A \(2\)
  2. B \(\frac{1}{2}\)
  3. C \(1\)
  4. D \(\frac{2}{3}\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(2\)

Step-by-step Solution

Detailed explanation

Given \(y = {\tan ^{ - 1}}\left( {\frac{{\sin x - \cos x}}{{\sin x + \cos x}}} \right)\) \( \Rightarrow y = {\tan ^{ - 1}}\left( {\frac{{\tan x - 1}}{{\tan x + 1}}} \right)\) \( \Rightarrow y = - {\tan ^{ - 1}}\left( {\frac{{1 - \tan x}}{{1 + \tan x}}} \right)\)…