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JEE Mains · Physics · STD 12 - 9. Ray optics and optical instruments

A light ray is incident on a glass slab of thickness \(4 \sqrt{3} \mathrm{~cm}\) and refractive index \(\sqrt{2}\). The angle of incidence is equal to the critical angle for the glass slab with air. The lateral displacement of ray after passing through glass slab is _______ \(\mathrm{cm}\). \(\left(\right.\) Given \(\left.\sin 15^{\circ}=0.25\right)\)

  1. A \(1\)
  2. B \(2\)
  3. C \(3\)
  4. D \(4\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(2\)

Step-by-step Solution

Detailed explanation

\(i=\theta_c\) \(\Rightarrow i=\sin ^{-1}\left(\frac{1}{\mu}\right)\) \(\Rightarrow i=45^{\circ}\) \(\text { and according to snell's law }\) \(1 \sin 45^{\circ}=\sqrt{2} \sin r\) \(\Rightarrow \mathrm{r}=30^{\circ}\)…
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