JEE Mains · Maths · STD 12 - 8. Application and integration
The area of the region \(\left\{(x, y): x^2 \leq y \leq\left|x^2-4\right|, y \geq 1\right\}\) is
- A \(\frac{3}{4}(4 \sqrt{2}-1)\)
- B \(\frac{4}{3}(4 \sqrt{2}-1)\)
- C \(\frac{4}{3}(4 \sqrt{2}+1)\)
- D \(\frac{3}{4}(4 \sqrt{2}+1)\)
Answer & Solution
Correct Answer
(B) \(\frac{4}{3}(4 \sqrt{2}-1)\)
Step-by-step Solution
Detailed explanation
Required area \(=2\left[\int \limits_1^2 \sqrt{ y } dy +\int \limits_2^4 \sqrt{4- y } dy \right]=\frac{4}{3}[4 \sqrt{2}-1]\)
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