JEE Mains · Physics · STD 12 - 4. Moving charges and magnetism
A solenoid of \(1000\) turns per metre has a core with relative permeability \(500\). Insulated windings of the solenoid carry an electric current of \(5\, A\). The magnetic flux density produced by the solenoid is (permeability of free space \(\left.=4 \pi \times 10^{-7} H / m \right)\)
- A \(\pi\;T\)
- B \(2 \times 10^{-3} \pi \;T\)
- C \(\frac{\pi}{5} \;T\)
- D \(10^{-4} \pi\;T\)
Answer & Solution
Correct Answer
(A) \(\pi\;T\)
Step-by-step Solution
Detailed explanation
\(B =\mu nI =\mu_{0} \mu_{ r } nI\) \(B =4 \pi \times 10^{-7} \times 500 \times 1000 \times 5\) \(B =\pi\) Tesla
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