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JEE Mains · Physics · STD 12 - 4. Moving charges and magnetism

A uniform conducting wire of length is \(24 {a}\), and resistance \({R}\) is wound up as a current carrying coil in the shape of an equilateral triangle of side \('a'\) and then in the form of a square of side \('a'.\) The coil is connected to a voltage source \({V}_{0}\). The ratio of magnetic moment of the coils in case of equilateral triangle to that for square is \(1: \sqrt{y}\) where \(y\) is ..... .

  1. A \(3\)
  2. B \(2\)
  3. C \(4\)
  4. D \(1\)
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Answer & Solution

Correct Answer

(A) \(3\)

Step-by-step Solution

Detailed explanation

In triangle shape \({N}_{{t}}=\frac{24 {a}}{3 {a}}=8\) In square \({N}_{{s}}=\frac{24 {a}}{4 {a}}=6\) \(\frac{{M}_{{t}}}{{M}_{3}}=\frac{{N}_{{t}} {IA}_{{t}}}{{N}_{{s}} {I}_{{s}}}[{I}\) will be same in both \(]\)…
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