JEE Mains · Physics · STD 11 - 1. units,dimensions and measurement
In a vernier callipers, each \(cm\) on the main scale is divided into \(20\) equal parts. If tenth vernier scale division coincides with nineth main scale division. Then the value of vernier constant will be \(\dots \; \times 10^{-2} \;mm\)
- A \(3\)
- B \(5\)
- C \(7\)
- D \(9\)
Answer & Solution
Correct Answer
(B) \(5\)
Step-by-step Solution
Detailed explanation
\(20 \; MSD =1 \; cm\) \(1 \; MSD =\frac{1}{20} \; cm\) \(10 \; VSD =9 \; MSD\) \(1 \; VSD =\frac{9}{10} \; MSD\) \(=\frac{9}{10} \times \frac{1}{20} \; cm\) \(1 VSD =\frac{9}{200} \; cm\) VC \(=1 MSD -1 \; VSD\) \(=\frac{1}{20} \; cm -\frac{9}{200} \; cm\)…
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