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JEE Mains · Physics · STD 11 - Units,dimensions and measurement
  • JEE Mains 2022
  • Medium
  • Numerical

In a vernier callipers, each \(cm\) on the main scale is divided into \(20\) equal parts. If tenth vernier scale division coincides with nineth main scale division. Then the value of vernier constant will be \(\dots \; \times 10^{-2} \;mm\)

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Answer & Solution

Correct Answer

(B) \(5\)

Step-by-step Solution

Detailed explanation

\(20 \; MSD =1 \; cm\)

\(1 \; MSD =\frac{1}{20} \; cm\)

\(10 \; VSD =9 \; MSD\)

\(1 \; VSD =\frac{9}{10} \; MSD\)

\(=\frac{9}{10} \times \frac{1}{20} \; cm\)

\(1 VSD =\frac{9}{200} \; cm\)

VC \(=1 MSD -1 \; VSD\)

\(=\frac{1}{20} \; cm -\frac{9}{200} \; cm\)

\(=\frac{1}{200} \times 10 \; mm\)

VC \(=5 \times 10^{-2} \; mm\)

Ans. \(5\)

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