JEE Mains · Maths · STD 11 - 4.1 complex nubers
The area of the triangle with vertices \(A ( z ), B ( iz )\) and \(C(z+i z)\) is
- A \(1\)
- B \(\frac{1}{2}|z|^{2}\)
- C \(\frac{1}{2}\)
- D \(\frac{1}{2}|z+i z|^{2}\)
Answer & Solution
Correct Answer
(B) \(\frac{1}{2}|z|^{2}\)
Step-by-step Solution
Detailed explanation
\(A =\frac{1}{2}| z || iz |\) \(=\frac{| z |^{2}}{2}\)
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