JEE Mains · Physics · STD 12 - 10. Wave optics
A beam of light consisting of wavelengths 650 nm and 550 nm illuminates the Young's double slits with separation of 2 mm such that the interference fringes are formed on a screen, placed at a distance of 1.2 m from the slits. The least distance of a point from the central maximum, where the bright fringes due to both the wavelengths coincide, is ___________ \(\times 10^{-5} m\).
- A 429
- B 550
- C 650
- D 380
Answer & Solution
Correct Answer
(A) 429
Step-by-step Solution
Detailed explanation
\(y=n\frac{\lambda D}{d}\) \(y_{1}=y_{2}\) \(n_{1}\lambda_{1}\frac{D}{d}=n_{2}\lambda_{2}\frac{D}{d}\) \(\frac{n_{1}}{n_{2}}=\frac{\lambda_{2}}{\lambda_{1}}=\frac{550}{650}=\frac{11}{13}\)…
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