JEE Mains · Physics · STD 11 - 3.2 motion in plane
A stone of mass \(900 \mathrm{~g}\) is tied to a string and moved in a vertical circle of radius \(1 \mathrm{~m}\) making \(10\ \mathrm{rpm}\). The tension in the string, when the stone is at the lowest point is _______. (if \(\pi^2=9.8\) and \(g=9.8 \mathrm{~m} / \mathrm{s}^2\) )
- A \(97 \mathrm{~N}\)
- B \(9.8 \mathrm{~N}\)
- C \(8.82 \mathrm{~N}\)
- D \(17.8 \mathrm{~N}\)
Answer & Solution
Correct Answer
(B) \(9.8 \mathrm{~N}\)
Step-by-step Solution
Detailed explanation
Given thaat \( \mathrm{m}=900 \mathrm{gm}=\frac{900}{1000} \mathrm{~kg}=\frac{9}{10} \mathrm{~kg} \) \( \mathrm{r}=1 \mathrm{~m} \) \( \omega=\frac{2 \pi \mathrm{N}}{60}=\frac{2 \pi(10)}{60}=\frac{\pi}{3} \mathrm{rad} / \mathrm{sec} \)…
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